I've tried everything, and I can't get this problem. Can someone help? Its really hard, but i'd appreciate it =D.
This is supposed to be solved using vectors, but I couldnt make the symbol for vectors. Hopefully you can understand it...
http://img254.imageshack.us/my.php?image...
D is the midpoint of AC and E is BC such that BE:EC=1:t, where t%26gt;0. Let DE:EF=1:7 and vector AD= vector a and vectorAB=vector b
a) i. Express vector AE in terms of t, vector a, and vector b.
ii. Express vector AE in terms of vector a and vector AF
iii. Show that vector AF= [vector a(9+7t)/(1+t)] + [vector b(8t)/(1+t)]
b). i. Suppose that A, B, and F are collinear.
i. Find the value of t.
ii. It is given that ||a||=3 and ||b||=2 and angle BAC=1/3, then find vector a • vector b
iii. Find AB • BC and AD•DE
iv. Does the circle passing through B, D, and C also pass through F? Explain your answer.
Extremely Hard Calc II question (vectors)?
We have, more or less,
AD = DC = a
AC = 2a
EC = tBE
EF = 7 DE
AB = b
AE = AB + BE = b + BE
Sorry. I just got started, and I'm already pretty bored here. :(
It would help if you did the first, easier parts yourself, and only asked about the later parts where you really get stuck.
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment