Are these vectors linearly independent??

Are the folowing list of vectors linearly independent??





A) { ( 2 , 1 ) , ( 1 , 2 ) , ( 2 , 2 ) }


B) { ( 1 , 0 , -4 , 7 ) , ( 5 , 3 , 1 , 6 ) , ( -2 , -1 , 0 , 8 ) , (0,0,0,0) }


C) { ( 1 , 2 , 4 ) , ( 0 , -1 , 1 ) , ( 3 , -1 , 1 ) }


D) { ( 2 , -1 , 1 ) , ( 4 , 0 , 2 ) }


E) { e1 , e1+e2,......,e1+e2+....+en } where ei in R^n is the vector which has 1 in the i-th place and 0 everywhere else!





HELP!!!

Are these vectors linearly independent??
A) No; we have two dimensions and three vectors.


B) No; contains the zero vector.


C) Check: a(1, 2, 4) + b(0, -1, -1) + c(3, -1, -1)


= (a + 3c, 2a - b - c, 4a - b - c)


= 0 %26lt;=%26gt; a = -3c, b+c = 2a, b+c = 4a


=%26gt; 2a = 4a and hence a = 0; from a = -3c we get c = 0, and then b = 0 also. So they are linearly independent.


D) Yes, two vectors that are not scalar multiples of each other are linearly independent.


E) Yes. Suppose c1 e1 + c2 (e1+e2) + ... + cn (e1+e2+...+en) = 0. Then we have


(c1+c2+...+cn, c2+...+cn, ..., cn-1 + cn, cn) = 0.


So cn = 0 and by successive back-substitution we get


cn-1 = 0, cn-2 = 0, ..., c2 = 0, c1 = 0.


So they are linearly independent.
Reply:ir2
Reply:D and e are right

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