Physics Vectors Questions.?

For each of the vectors below,





I.) convert it to the form it is not already in (size%26amp;direction, or components)


(Note: cw=clockwise, ccw=counterclockwise)





A.) Vav = 5 m/s, 5degree cw from –y axis





vav x = ??? m/s


vav y = ??? m/s





c.) Qx = -2 m, Qy = +6 m





Q = ? m, ? degrees cw from –x axis

Physics Vectors Questions.?
Try to understand how these kinds of problems are so easy to work out!





Vav = 5 at 5 degrees clock wise from (-y). This is like saying 5 deg west of south!





Vav x = 5*sine5 = 0.435 west; or to –x


Vav y = 5 cosine 5 = 4.98 south or –y





Now for the second problem you have Qx =-2, this is west.


Qy =6. This is north.





The sum or the resultant vector = sqrt((-x)^2 +(y^2)= sqrt(4+36) = 6.32 at an angle theta which is tan^-1 theta = -2/6 = -0.3333; tan^-1 (-0.3333) = 18.43 degrees west of the north or 108.43 degrees in the second quarter, where tangent is negative in the 2nd quarter.


Now if you want the angle clockwise from -x, it will be 71.57 degrees clockwise from -x. This is the same as 18.43 anticlockwise from the +Y axis





That is it.





I hope I have helped!