Help with math, vectors???

working with vectors when components arent given:





here's an example


Given A (-1,5) and C(0, -11)


Find


1) AC (Where A is the tail, and C is the tip)


the answer is (1, -16) why is that doesnt -1+ 0= -1 and 5 + -11= -6?


Another example


B (2, -3) A (-1,5)


Find


2) BA


BA= (-3,8)= b


Find the rest


A (-1,5) B(2,-3) C(0,-1) D (-6,9) O(0,0)


3) AD


4)DB


5)OC


6) DA


7)BB





Find the Equilibrant for the following resultant





given F1= (-2,5), F2(3, -7) F3 (-6,2)





F- 2F2-3F3


= 2 (-2,5) -3(-6, -2)


=(-4, -10)+ (18, 6)


=(14, 16) how do you get 16 from -10 + 6?


therefore E (-14, -16)

Help with math, vectors???
Given A (-1,5) and C(0, -11)


Find


1) AC (Where A is the tail, and C is the tip)





Vector AC has coordinates


(xC-xA, yC-yA) = (0-(-1), -11-5) = (1, -16)


********************************





Another example


B (2, -3) A (-1,5)


Find


2) BA


BA = (-1-2, 5-(-3)) = (-3, 8)





**************************************...


Find the rest


A (-1,5) B(2,-3) C(0,-1) D (-6,9) O(0,0)


3) AD


AD = (-6 +1, 9 -5) = (-5, 4)


4)DB


DB = (-6-2, 9+3) = (-8, 12)


5)OC


OC = (0-0, 0+1) = (0,1)


6) DA


DA = -AD = (5, -4)


7)BB


BB = (2-2, -3 -(-3)) = (0.0) (Null Vector)


***********************





Find the Equilibrant for the following resultant





given F1= (-2,5), F2(3, -7) F3 (-6,2)





F = 2F2-3F3


where is F1 ?


Check this!





F = 2F2-3F3=


F = 2(3, -7) -3(-6,2)


F = (6+18 , -14 -6)


F = (24, -20)








Please check your last question for typos
Reply:If it's AC then subtract C from A. (C-A)


A(-1,5) and C(0,-11); x=0-(-1)=1, y=-11-(5)=-16. Remember that AC is now a vector, so write it in vector component form (AC=1i-16j) or in short form %26lt;1,-16%26gt;.





Just look at the order of the letters and subtract the second letter from first. BA (B-A), AD(D-A), and so on.





For the equilibrant problem just distribute the constants in front of the forces.Ex. -2F2=%26lt;-6,14%26gt;, then add the components.