Two horizontal forces act on a 3.5 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is F1 = (3.1 N)i + (7.8 N)j. Find the acceleration of the chopping block in unit-vector notation when the other force is (a) F2 = (-3.1 N)i + (-7.8 N)j, F(b) 2 = (-3.1 N)i + (7.8 N)j, and (c) F2 = (3.1 N)i + (-7.8 N)j.
Force and Vectors?
I'llshow you how to do part a. You can do the others - homework is good for the soul %26amp; it teaches you how to do things yourself :%26gt;)
a. Net force = Fn = F1 + F2 (everything is a vector)
accleration a = Fn/m = (F1 + F2)/m (m is mass, a scalar)
a =[3.1 i + 7.8 j + (-3.1) i + (-7.8) j]/3.5 m/s^2
a = (0 i + 0 j)/3.5 m/s^2 = 0 i + 0 j m/s^2 no accleration the forces cancel.
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