Can someone help me solve this problem about vectors?

a quarterback throws a football with a speed of 48 feet per second at an angle of 45 degrees upward from the ground. the vector that describles the motion of the football is





a 34i + 34j


b 68i + 68j


c 30i + 30j


d 34i - 34j

Can someone help me solve this problem about vectors?
the angle is 45 degrees





construct a triangle that has hypotenuse of 48


by pythagorean theorem


a^2+b^2=c^2





a and b are the same for a 45 degree triangle


thus





2a^2=48^2


2a^2=2304


a^2=2304/2


a=48/sqrt2 which is approx 34





so 34i +34j is correct because the ball is going up initially





34i-34j is throwing the ball down


68i+68j is multiplying by sqrt2 , not dividing
Reply:None of the above.





If you *throw* a football at an angle of 45 degrees upward, the football doesn't *travel* at an angle of 45 degrees. It goes in an arc, and eventually hits the ground.
Reply:the answer is A
Reply:The magnitude of the vector is 48 fps, and its direction is 45 deg from the x-axis.


The x-component of the vector is 48cos45 = 48(0.707) = 34


The y component of the vector is 48Sin45 = 48(0.707) = 34


Therefore, the vector is 34 i + 34 j; answer a)
Reply:what's your vector Victor?
Reply:My brain hurts.