■■■■■Please give me detailed solution■■■■■
1.If vectorA=(1,0,3),vectorB=(5,2,6),findθAB=...
2.Show that vectors vector a=(4,0,-1),vector b=(1,3,4),vector c=(-5,-3.-3)
form the sides of a triangle. Is this a right triangle?
Calculate the area of the triangle
3.(a)Convert points P(1,3,5),T(0,-4,3),and S(-3,-4,-10) from Cartesian to cylindrical
and spherical coordinates.
(b)Transform vector
vector Q= ( [√(x²+y²)/√(x²+y ²+z²)] , 0 , -yz/√(x²+y²+z²) )
to cylindrical and spherical coordinates
(c)evaluate vector Q at T in the three coordinate systems
Urgent problem!(Calculus)How to solution this problem??
1. cosθ=A*B / (|A|*|B|)=(1*5+0*2+3*6) / 5√ 26
=81.171
2. assume the angle of vectors of a and b is "m"
so cos m= a*b/(|a|*|b|)=0 because cos90=0
m=90...so it is a right triangle...
|a| and |b| are representing the right-angled sides of the triangle.
|a|=√17; |b|=√26
S=|a|*|b| / 2 =10.5
3. P(1,3,5) to cylindrical coordinates.......
r=√1+9 =√10....
θ= tan^(-1)3=71.6
z= 5
In terms of x , y , and z
x= r.cosθ =√10*71.6 =226
y= r.sinθ = 0.95*√10= 3
z=5
so its (226,3,5)
ditto, T 's doesn't have cylindrical coordinates
S 's cylindrical coordinates is (0.6, -0.8, -10)
......................(that's all i know..)
garden centre
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