A vector A has a magnitude of 54.0 m and points in a direction 20.0° below the x axis. A second vector, B, has a magnitude of 70.0 m and points in a direction 52.0° above the x axis.
(a) Sketch the vectors A, B, and C = A + B. (Do this on paper. You do not need to turn this in,but use it as a control of your calculations.)
to find thee x and y component of vector C
as well find thee magintude and direction
Please help me with this math problem?
x comp = 54cos(-20) + 70cos(52) = 93.84m
y comp = 54sin(-20) + 70sin(52) = 36.69m
magnitude = sqrt[ 93.84^2 + 36.69^2 ] =100.76m
tan(x) = 36.69/93.84
x = 21.35 degrees above the x-axis
Reply:0
x comp = 54cos(-20) + 70cos(52) = 93.84m
y comp = 54sin(-20) + 70sin(52) = 36.69m
magnitude = sqrt[ 93.84^2 + 36.69^2 ] =100.76m
tan(x) = 36.69/93.84
x = 21.35 degrees above the x-axis
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