given
A = (a1,a2,a3),B = (b1,b2,b3) , C =(c1,c2,c3)
how to prove
A x ( B x C ) = ( A .C) B - ( A . B )C
*A,B,C are vectors
Help-----proof-----------vecto...
Define V = B x C; clearly V is perpendicular to the plane of B and C.
Thus A x V must be IN the plane of B and C.
Let A x V = λ B + µ C;
Then A . [A x (B X C] = λ A . B + µ A . C
this implies that λ A . B + µ A . C = 0.
This relationship is certainly satisfied by λ = A.C
and µ = - A.B.
We have shown that A x (B x C) = (A.C) B - (A.B) C is a possibility, but my method shows only that
A x (B x C) = p {(A.C) B - (A.B) C} where p is a scalar multiplier.
It should be possible to show that p = 1.
apricot
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