Another physics 111 question?

You are given vectors A = 4.8i - 6.3j and B = - 4.0i- 6.5j . A third vector C lies in the xy-plane. Vector C is perpendicular to vector A and the scalar product of C with B is 15.0.





Find the x-component of vector C and Find the y-component of vector C





thanks!

Another physics 111 question?
This involves dot products...





A.*C = 0


B.*C = 15





A.*C = (4.8)*x + (-6.3)*y = 0


B.*C = (-4)*x + (-6.5)*y = 15





Two equation with 2 unkowns....





A = [4.8 -6.3; -4 -6.5]


x = [x ; y]


b = [0 ; 15]





Ax = b


x = A^-1*b





x = [-1.676 ; -1.277]





C = -1.676 i - 1.277 j





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