I have two vectors, they are nearly linearly dependent. I would like to normalize them in a least squared sense. How can I do this?
How can I find a constant c such that norm(c*v1 - v2) is as close to 0 as possible?
The square of the norm of c*v_1 -v_2 is the inner product
%26lt;c_1 -v2, c v1 -v2%26gt;
=c^2 %26lt;v1,v1%26gt;-2c%26lt;v1,v2%26gt;+%26lt;v2,v2%26gt;.
This is a quadratic in c so is minimized when
c=%26lt;v1,v2%26gt;/%26lt;v1,v1%26gt;
Reply:Project vector v2 on v1. The projection is the c*v1 you are looking for.
Algebraic derivation: minimize the squared norm.
[1] ... |c*v1 - v2|^2 is minimal
[2] ... c^2|v1|^2 - 2c(v1.v2) + |v2|^2 is minimal
The minimum of ax^2 + bx + c is found when x = -b/2a; here:
[3] ... c = (v1.v2) / |v1|^2
Reply:write it out (this depends on your norm i use euclidean)
: r(c) = (cx1-x2)^2 +(cy1 - y2)^2
v1 =(x1,y1), v2=(x2,y2) all given.
r(c) is a parabole minimize for c.
Reply:c*v1 -v2 Set this to 0
c*v1 -v2 =0 Add v2 to both sides
c*v1 = v2 Now divide both sides by v1
c = v2/v1 Now plug this value into c and when you do the original problem it should equal 0.
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