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vector A has a magnitude of 188units and points at an angle 30 north west.vector B points an angle of 50 north east.vector C points at an angle of 20 south west.the 3 vectors add to give a resultant vector that is zero.using components ,find the magnitudes of vectors B and C

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188cos30 + Bcos50 = Ccos20


188sin30 + Csin20 = Bsin50


Bcos50 - Ccos20 = - 188cos30


Bsin50 - Csin20 = 188sin30





-Bsin50cos50 + Csin50cos20 = 188sin50cos30


Bsin50cos50 - Ccos50sin20 = 188cos50sin30





C(sin50cos20 - Ccos50sin20) = 188(sin50cos30 + cos50sin30)


C = 188(sin50cos30 + cos50sin30)/(sin50cos20 - Ccos50sin20)


C = 370.28771513259023032189537724566


C ≈ 370.2877





188sin30 + Csin20 = Bsin50


B = 288.03271061273574123609963660884


B ≈ 288.0327





check:


188cos30 + Bcos50 = Ccos20


347.95663347776958075252764472438 =?347.95663347776958075252764472433
Reply:Helmut, it's ridiculous to include that many digits in your answer! The data was only given to two or three places, so that's all that counts in the answer. Sheesh!

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