Sunday, August 2, 2009

Acceleration from 3 force vectors...how do you get it?

Three forces acting on an object are given by F1 = ( 1.55 i - 1.90 j ) N, F2 = ( - 5.20 i - 3.15 j ) N, and F3 = ( - 50.0 i + 44.0 j ) N. The object experiences an acceleration of magnitude 3.70 m/s2.


(a) What is the direction of the acceleration?


wrong check mark° (from the positive x axis)


(b) What is the mass of the object?


kg


(c) If the object is initially at rest, what is its speed after 16.0 s?


m/s


(d) What are the velocity components of the object after 16.0 s?


( i + j ) m/s

Acceleration from 3 force vectors...how do you get it?
Add all the i components


Add all the j components


Find the mag of the resultant


a)From the two components of the resuntant force determine the angle it makes with the x-axis.


b)Divide the mag of resultant F by a to get m ( Newton's 2nd law)


c)Use kinematics and the formula v = at, to find the final speed. If "a" is a vector with i and j components, then "v" will be a vector with i and j components, because you will have multiplied the vector "a" by the scalar "t" to get the vector "v".





d)What is the coefficient of the unit "i" vector?


What is the coefficient of the unit "j" vector?


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